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Oracle Database: SQL Fundamentals I Certification Exam

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Oracle 1Z0-051 Free Practice Questions

Q1. - (Topic 1) 

Which two are true about aggregate functions? (Choose two.) 

A. You can use aggregate functions in any clause of a SELECT statement. 

B. You can use aggregate functions only in the column list of the select clause and in the WHERE clause of a SELECT statement. 

C. You can mix single row columns with aggregate functions in the column list of a SELECT statement by grouping on the single row columns. 

D. You can pass column names, expressions, constants, or functions as parameter to an aggregate function. 

E. You can use aggregate functions on a table, only by grouping the whole table as one single group. 

F. You cannot group the rows of a table by more than one column while using aggregate functions. 

Answer: A,D 

Q2. - (Topic 1) 

The following data exists in the PRODUCTS table: PROD_ID PROD_LIST_PRICE 

123456 152525.99 

You issue the following query: 

SQL> SELECT RPAD(( ROUND(prod_list_price)), 10,'*') 

FROM products 

WHERE prod_id = 123456; 

What would be the outcome? 

A. 152526**** 

B. **152525.99 

C. 152525** 

D. an error message 

Answer:

Explanation: 

The LPAD(string, length after padding, padding string) and RPAD(string, length after padding, padding string) functions add a padding string of characters to the left or right of a string until it reaches the specified length after padding. 

Q3. - (Topic 1) 

Which arithmetic operations can be performed on a column by using a SQL function that is built into Oracle database? (Choose three.) 

A. addition 

B. subtraction 

C. raising to a power 

D. finding the quotient 

E. finding the lowest value 

Answer: A,C,E 

Q4. - (Topic 2) 

Which two statements are true about WHERE and HAVING clauses? (Choose two) 

A. A WHERE clause can be used to restrict both rows and groups. 

B. A WHERE clause can be used to restrict rows only. 

C. A HAVING clause can be used to restrict both rows and groups. 

D. A HAVING clause can be used to restrict groups only. 

E. A WHERE clause CANNOT be used in a query of the query uses a HAVING clause. 

F. A HAVING clause CANNOT be used in sub queries. 

Answer: B,D Explanation: 

B: WHERE clause cannot be use to restrict groups 

WHERE clause cannot be use when there is group functions. 

D: A HAVING clause can only e used to restrict GROUPS. 

Note: HAVING clause to specify which groups are to be displayed and thus further restrict the groups on the basis of aggregate information. The Oracle server performs the following steps when you use the Having clause 

1. 

rows are grouped 

2. 

the group function is applied to the group 

3. 

the group that match the criteria in the Having clause are displayed. 

Incorrect Answers : 

A. Where clause cannot be use to restrict groups 

C. A HAVING clause can only e used to restrict GROUPS. 

E. WHERE clause cannot be use when there is group function, instead HAVING is to be use. 

F. There is no constraint to use HAVING clause in a sub queries. 

Refer: Introduction to Oracle9i: SQL, Oracle University Student Guide, Aggregating Data using Group Functions, p. 5-20 

Q5. - (Topic 1) 

View the Exhibit and examine the structure of the CUSTOMERS table. 

You have been asked to produce a report on the CUSTOMERS table showing the customers details sorted in descending order of the city and in the descending order of their income level in each city. Which query would accomplish this task? 

A. SELECT cust_city, cust_income_level, cust_last_name FROM customers ORDER BY cust_city desc, cust_income_level DESC; 

B. SELECT cust_city, cust_income_level, cust_last_name FROM customers ORDER BY cust_income_level desc, cust_city DESC; 

C. SELECT cust_city, cust_income_level, cust_last_name 

FROM customers 

ORDER BY (cust_city, cust_income_level) DESC; 

D. SELECT cust_city, cust_income_level, cust_last_name FROM customers ORDER BY cust_city, cust_income_level DESC; 

Answer:

Q6. - (Topic 1) 

View the Exhibit and examine the structure of the SALES table. 

The following query is written to retrieve all those product IDs from the SALES table that have more than 55000 sold and have been ordered more than 10 times. 

Which statement is true regarding this SQL statement? 

A. It executes successfully and generates the required result. 

B. It produces an error because COUNT(*) should be specified in the SELECT clause also. 

C. It produces an error because COUNT(*) should be only in the HAVING clause and not in the WHERE clause. 

D. It executes successfully but produces no result because COUNT(prod_id) should be used instead of COUNT(*). 

Answer:

Explanation: 

Restricting Group Results with the HAVING Clause 

You use the HAVING clause to specify the groups that are to be displayed, thus further 

restricting the groups on the basis of aggregate information. 

In the syntax, group_condition restricts the groups of rows returned to those groups for 

which the specified condition is true. 

The Oracle server performs the following steps when you use the HAVING clause: 

1. 

Rows are grouped. 

2. 

The group function is applied to the group. 

3. 

The groups that match the criteria in the HAVING clause are displayed. 

The HAVING clause can precede the GROUP BY clause, but it is recommended that you 

place the GROUP BY clause first because it is more logical. Groups are formed and group 

functions are calculated before the HAVING clause is applied to the groups in the SELECT 

list. 

Note: The WHERE clause restricts rows, whereas the HAVING clause restricts groups. 

Q7. - (Topic 2) 

Evaluate the following SQL statement: 

SQL> SELECT cust_id, cust_last_name FROM customers WHERE cust_credit_limit IN (select cust_credit_limit FROM customers WHERE cust_city ='Singapore'); 

Which statement is true regarding the above query if one of the values generated by the subquery is NULL? 

A. It produces an error. 

B. It executes but returns no rows. 

C. It generates output for NULL as well as the other values produced by the subquery. 

D. It ignores the NULL value and generates output for the other values produced by the subquery. 

Answer:

Q8. - (Topic 1) 

Examine the structure of the EMPLOYEES and NEW_EMPLOYEES tables: 

Which DELETE statement is valid? 

A. DELETE FROM employeesWHERE employee_id = (SELECT employee_id FROM employees); 

B. DELETE * FROM employeesWHERE employee_id=(SELECT employee_id FROM new_employees); 

C. DELETE FROM employeesWHERE employee_id IN (SELECT employee_id FROM new_employees WHERE name = ‘Carrey’); 

D. DELETE * FROM employeesWHERE employee_id IN (SELECT employee_id FROM new_employees WHERE name = ‘Carrey’); 

Answer:

Q9. - (Topic 1) 

View the Exhibit and examine the structure of the CUSTOMERS table. Evaluate the following SQL statement: 

Which statement is true regarding the outcome of the above query? 

A. It executes successfully. 

B. It returns an error because the BETWEEN operator cannot be used in the HAVING clause. 

C. It returns an error because WHERE and HAVING clauses cannot be used in the same SELECT statement. 

D. It returns an error because WHERE and HAVING clauses cannot be used to apply conditions on the same column. 

Answer:

Q10. - (Topic 1) 

View the Exhibit and examine the structure of the PROMOTIONS table. 

You have to generate a report that displays the promo name and start date for all promos that started after the last promo in the 'INTERNET' category. 

Which query would give you the required output? 

A. 

SELECT promo_name, promo_begin_date FROM promotions WHERE promo_begin_date > ALL (SELECT MAX(promo_begin_date) FROM promotions )AND promo_category = 'INTERNET' 

B. 

SELECT promo_name, promo_begin_date FROM promotions WHERE promo_begin_date IN (SELECT promo_begin_date FROM promotions WHERE promo_category='INTERNET'); 

C. 

SELECT promo_name, promo_begin_date FROM promotions WHERE promo_begin_date > ALL (SELECT promo_begin_date FROM promotions WHERE promo_category = 'INTERNET'); 

D. 

SELECT promo_name, promo_begin_date FROM promotions WHERE promo_begin_date > ANY (SELECT promo_begin_date FROM promotions WHERE promo_category = 'INTERNET'); 

Answer:

Q11. - (Topic 1) 

You are currently located in Singapore and have connected to a remote database in Chicago. You issue the following command: 

Exhibit: 

PROMOTIONS is the public synonym for the public database link for the PROMOTIONS table. 

What is the outcome? 

A. Number of days since the promo started based on the current Chicago data and time 

B. Number of days since the promo started based on the current Singapore data and time. 

C. An error because the WHERE condition specified is invalid 

D. An error because the ROUND function specified is invalid 

Answer:

Q12. - (Topic 1) 

Which three statements/commands would cause a transaction to end? (Choose three.) 

A. COMMIT 

B. SELECT 

C. CREATE 

D. ROLLBACK 

E. SAVEPOINT 

Answer: A,C,D 

Q13. - (Topic 1) 

Which statement is true regarding the INTERSECT operator? 

A. It ignores NULL values 

B. The number of columns and data types must be identical for all SELECT statements in the query 

C. The names of columns in all SELECT statements must be identical 

D. Reversing the order of the intersected tables the result 

Answer:

Explanation: 

INTERSECT Returns only the rows that occur in both queries’ result sets, sorting them and 

removing duplicates. 

The columns in the queries that make up a compound query can have different names, but 

the output result set will use the names of the columns in the first query. 

Q14. - (Topic 1) 

View the Exhibit and examine the structure of the CUSTOMERS table. Evaluate the query statement: 

What would be the outcome of the above statement? 

A. It executes successfully. 

B. It produces an error because the condition on CUST_LAST_NAME is invalid. 

C. It executes successfully only if the CUST_CREDIT_LIMIT column does not contain any null values. 

D. It produces an error because the AND operator cannot be used to combine multiple BETWEEN clauses. 

Answer:

Q15. - (Topic 2) 

Examine the structure proposed for the TRANSACTIONS table: 

Which statements are true regarding the creation and storage of data in the above table structure? (Choose all that apply.) 

A. The CUST_STATUS column would give an error. 

B. The TRANS_VALIDITY column would give an error. 

C. The CUST_STATUS column would store exactly one character. 

D. The CUST_CREDIT_LIMIT column would not be able to store decimal values. 

E. The TRANS_VALIDITY column would have a maximum size of one character. 

F. The TRANS_DATE column would be able to store day, month, century, year, hour, minutes, seconds, and fractions of seconds. 

Answer: B,C 

Explanation: 

VARCHAR2(size)Variable-length character data (A maximum size must be specified: 

minimum size is 1; maximum size is 4,000.) 

CHAR [(size)] Fixed-length character data of length size bytes (Default and minimum size 

is 1; maximum size is 2,000.) 

NUMBER [(p,s)] Number having precision p and scale s (Precision is the total number of 

decimal digits and scale is the number of digits to the right of the decimal point; precision 

can range from 1 to 38, and scale can range from –84 to 127.) 

DATE Date and time values to the nearest second between January 1, 4712 B.C., and 

December 31, 9999 A.D. 

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